pi + 1 >= 0 et pi - 1 >= 0 donc :
B = 2|pi + 1| - 3|pi - 1| = 2(pi + 1) - 3(pi - 1) = 2pi + 2 - 3pi + 3 = -pi + 5
pi - 3 >= 0 donc
C = |pi - 3|*|3 - pi| = (pi - 3)*(pi - 3) = (pi - 3)² = pi² -6pi + 9
V5 - 1 >= 0 donc
D = 4|V5 - 1| - 8|1 - V5| = 4(V5 - 1) - 8(V5 - 1) = -4(V5 - 1) = 4 - 4V5
x - 2 <= 0 et 1 - x <= 0 donc
E = 12|x - 2| + 13|1 - x| = 12(2 - x) + 13(x - 1) = 24 - 12x + 13x - 13 = x + 11